3(2a-5) = 12-7a
6a-15=12-7a
6a+7a=12+15
13a= 27
27=3c-3(6-2c)
27=3c-18+6c
27+18=3c+6c
45=9c
C=45/9
C=5
6c-8-2c=-16
6c-2c=-16+8
4c=-8
C=-8/4
C=-2
Answer:
Original price of ticket = $12.5
Step-by-step explanation:
Given:
8% amount = $1
Find:
Original price of ticket
Computation:
Original price of ticket = 1(100/8)
Original price of ticket = $12.5
Answer:
Car = 10 miles/hour
Bus = 20 miles/hour
Step-by-step explanation:
Here,
Let, the value of the speed of the bus = X
the value of the speed of the car = 2X - 30 (As the speed of the car is 30mph slower than twice)
According to the question,
2X - 20 = 2*(2x-30)
or, 2X - 20 = 4X-60
or, 2X = 40
x = 20
Therefore, the speed of the bus, x = 20 miles/hour
So, the speed of the car is (2*20-30) mph = (40 - 30) mph = 10 miles/hour.
Answer:
145
Step-by-step explanation:
just use a calculator
Step-by-step explanation:
given :
2x - 3y = 11
-6x + 8y = 34
find : the solutions of the system by using Cramers Rule.
solutions:
in the matrix 2x2 form =>
[ 2 -3] [x] [11]
=
[-6 8] [ y] [34]
D =
| 2 -3 |
|-6 8 |
= 8×2 - (-3) (-6)
= 16-18 = -2
Dx = | 11 -3 |
| 34 8 |
= 11×8 - (-3) (34)
= 88 + 102
= 190
Dy = | 2 11 |
|-6 34 |
= 2×34 - (-6) (11)
= 68 + 66
= 134
x = Dx/D = 190/-2 = -95
y = Dy/D = 134/-2 = -67
the solutions = {-95, -67}
