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3 years ago

Which statements could be used to prove that AABC and AA'B'C' are congruent?

Mathematics

1 answer:

Assoli18 [71]3 years ago

5 0

I think it’s D I am not sure tho

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Plz help! I dont understand this

strojnjashka [21]

Solve for x the. You can find your answer from there.

8 0

3 years ago

Which expression is equivalent to 36^-1/2

inn [45]

ANSWER

$( {36})^{ (- \frac{1}{2}) } = \frac{1}{6}$

EXPLANATION

The given expression is

${36}^{( - \frac{1}{2} )}$
This is having a negative index. We must first of all change to a positive index.

Recall that,

${a}^{ - m} = \frac{1}{ {a}^{m} }$

We apply this law of exponents to get,

${36}^{( - \frac{1}{2} )} = \frac{1}{ {36}^{( \frac{1}{2} )} }$

We cab rewrite the given expression to obtain;

${36}^{( - \frac{1}{2} )} = \frac{1}{ \sqrt{36} }$

This will simplify to give us,

${36}^{( - \frac{1}{2} )} = \frac{1}{ 6 }$

6 0

3 years ago

Read 2 more answers

Find AM in the parallelogram if PN =15 and AO = 6. The diagram is not to scale.

valentinak56 [21]

Answer:

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

The diagonals are PN and MO. The point A divides PN into 2 equal segments as well as MO into 2 equal segments.

Since AO = 6, MA should also be equal. Hence, MA (or AM) = 6.

The correct answer is AM = 6

7 0

3 years ago

The force of a 5.0 kg bowling ball with an acceleration of 3m/s2 is 15 N.<br> True<br> False

sladkih [1.3K]

True. Force is equal to mass times acceleration. So if we have a mass of 5kg and an acceleration of 3. Then the force is 15 N

7 0

3 years ago

For a craft, each student will need five rubber bands. There are eight students. What rubber bands come in bags of 9. How many b

gizmo_the_mogwai [7]

Answer:

In total 5 packets of rubber bands are needed.

Out of which 5 rubber bands are left.

Step-by-step explanation:

The number of rubber bands needed by 1 student = 5

The total number of students = 8

So, the total rubber bands needed by all students

= Total students x Number of rubber bands needed by 1 student

= 8 x 5 = 40 bands

Now 1 packet of rubber bands = 9 bands

⇒ 2 packets = 2 x ( 9 bands) = 18 bands

⇒ 3 packets = 3 x ( 9 bands) = 27 bands

Similarly, 4 packets = 36 bands , 5 packets = 45 bands

Now, if we buy 4 packet of bands, there are 36 rubber bands which are LESS THAN THE TOTAL STUDENTS.

So, we buy 5 packets.

We have in total 45 bands, but the total students = 40

So, the number of left rubber bands = Total bands - Total students

= 45 - 40 = 5

Hence, in total 5 packets of rubber bands are needed, and out of which 5 rubber bands are left.

5 0

3 years ago