4 x 5/7 = 20/7
20/7 = 2 6/7
Answer:
C.) $2.00 per pound
Hope This Helps! Have A Nice Day!
1. DE || AB - Given
2. DE 1/2 AB - side splitter theorem
3. CD/CA = CE/CB - sst = proportioned sides
Since you're looking for the chance that the defective player occurs twice, you need to find the chance your friend receives a defective player given that you also receive one. The chance you receive a defective player is 4%, or 0.04. If you friend also receives a defective player, then the chance of both occurring is 4% of 4%, or 0.04 * 0.04, which equals 0.0016. So the probability that you can a friend both receive a defective player is 0.16%.
It would be (A) because all the points match the numbers above it
