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3 years ago

Please help me! what is the end behavior of f(x)?

Mathematics

1 answer:

notsponge [240]3 years ago

6 0

Dddddddddddddddd i think

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I need help asap someone please help me i dont understand this question so can someone help me

eduard

Answer:

we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

Step-by-step explanation:

Given the expression

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}$

$=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}$

cancel the common factor: 2

$=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}$

cancel the common factor: p

$=\frac{2p+1}{p^2\left(4p^2-1\right)}$

$=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}$

cancel the common factor: 2p+1

$=\frac{1}{p^2\left(2p-1\right)}$

Expanding

$=\frac{1}{2p^3-p^2}$

Thus, we conclude that:

$\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}$

7 0

2 years ago

Give the quotient in simplest form:

11Alexandr11 [23.1K]

Answer:

Answer should be 5/2 I thinkkkkk

3 0

3 years ago

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Need to draw an area model to multiply 3x31

Luda [366]

You would do three square in length and 31 in width

6 0

2 years ago

An auditorium has a seating capacity of 1500. For an upcoming event community event theater play, tickets cost $4 for adults and

hichkok12 [17]

Answer:

from the question, the expression for the total amount of money from tickets sales will be T=4 × the number of children

4 0

2 years ago

Please help me and thank you

Anna007 [38]

Answer:

the location of Y is 9.5

Step-by-step explanation:

-7+26 = 19

19/2 = 9.5

4 0

2 years ago

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