Answer:
should be -29.29 %
Step-by-step explanation:
Divide 141 by 73
73 only goes into 141 once
Answer:
505.8
Step-by-step explanation:
4215x0.12=505.8
Option C:
is equivalent to the given expression.
Solution:
Given expression:

To find which expression is equivalent to the given expression.

Using exponent rule: 


Using exponent rule: 


Divide both numerator and denominator by the common factor –6.


Therefore,
is equivalent to the given expression.
Hence Option C is the correct answer.