1021 / 5 = 204.20.....each girl got 204 stickers.....with a remainder of 1 sticker
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
= [- 12 ± √(144-64d) ] / (-32)
= [- 12 ± √16(9-4d)] / (-32)
= [- 12 ± 4√(9-4d)] / (-32)
= 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
Answer:
y = 56
Step-by-step explanation:
the midsegment SV is half the length of the side TU , that is
y - 9 = 
(y + 38) ← multiply both sides by 2 to clear the fraction
2y - 18 = y + 38 ( subtract y from both sides )
y - 18 = 38 ( add 18 to both sides )
y = 56
By addition of all the exercise and substracting it from 1 hourJavier runs on treadmill on Monday is 0.40 hour.
Now According to the question javier completed 3 repetitions of each exercise so by multiplication time taken by javier to complete each exercise is as follow;
Squats = 0.8*3= 0.24 hour
Crunches = 0.03*3 = 0.09 hour
Lunges = 0.04*3 = 0.12 hour
curls = 0.05*3 = 0.15 hour
we can calculate total time taken to complete all exercise by Addition is,
0.24 + 0.09 + 0.12 + 0.15
0.60 hour
time taken on treadmill by javier;
1 hour - 0.60 hour
0.40 hour
Read more about Addition here:
brainly.com/question/20658817
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