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Eddi Din [679]
3 years ago
15

How many possible values for y are there where y= Cos -1 0

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

B) 1 possible value

FOR THIS SPECIFIC INSTANCE

Step-by-step explanation:

If it is Cos -1 (0) and cos is capitalized, that means it is a function and you apply restrictions. Based on the restrictions you get one possible value (I think the value is pi/2)

However, if the problem is cos -1(0) with no capitalization, it is a relation meaning values are infinite because of repetitions. The answers would be pi/2 and 3pi/2 and both would be added/subtracted by 2n(pi).

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Hello everyone can you answer this for me? What is A in the equation attached? Please and thank you.
lapo4ka [179]

Answer:

a = 6

Step-by-step explanation:

Hello!

Solve:

  • 4(3a - 4) = 56
  • 3a - 4 = 14          (factoring out 4)
  • 3a = 18               (adding 4 to both sides)
  • a = 6                   (dividing by 3)

Another way:

  • 4(3a - 4) = 56
  • 12a - 16 = 56        (distributive property)
  • 12a = 72               (moving like terms)
  • a = 6                    (dividing by 12)

Distributive Property of Multiplication:

The process of distributing the outside factor to the terms in the parenthesis.

Example:

4(3a - 4)\\\\4(3a) - 4(4)\\\\12a - 16

7 0
2 years ago
Read 2 more answers
Write an equation of a line containing the point (-2, 1) and is perpendicular to y= -1/4x-4
frosja888 [35]

the answer should be -4

hope this is correct for you and this helped

6 0
3 years ago
Y divided by 6 equal 9
kirza4 [7]
Y = 54 if your solving for y
8 0
3 years ago
Pleaseee answer asap.. thanks
andreyandreev [35.5K]

Answer:

the answer will be D

Step-by-step explanation:

5 0
3 years ago
3x^2 -5x -2=0
Kipish [7]

Answer:

Step-by-step explanation:

1. Find two numbers that add to make the coefficient of x (in this case, -5) and that multiply to make the constant term multiplied by the coefficient of x^2 (in this case, -2 x 3 = -6)

Two numbers that work are -6 and +1

-6 x +1 = -6

-6 + -1 = -5

2. Split the middle term into the two numbers that you found.

3x^2 -6x +x -2 = 0

I've put the -6 on the left side because in our next step, when we factorise, it will be easier than having the numbers the other way around.

3. Factorise the left side by taking out common factors from each pair. The pairs I'm talking about here are '3x^2 and -6x', and 'x and -2'

3x (x-2) +1 (x-2) = 0

4. You now have two numbers both being multiplied by the term x-2. We can rearrange this equation to give us two brackets being multiplied by each other.

(3x + 1) (x-2) = 0

5. According to the Null Factor Law, if two terms are multiplied together and the result is 0, then one of those terms must be 0. Make both terms equal to 0 and solve each for x.

3x + 1 = 0              x-2 = 0

3x = -1                   x = 2

x = -1/3

6. The solutions to this equation are x = 2 and x = -1/3

6 0
3 years ago
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