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Ivanshal [37]
2 years ago
5

What does the diagram at the left tell us about the two

Mathematics
1 answer:
ANEK [815]2 years ago
7 0

Answer:

Its enlargement

Step-by-step explanation:

Its enlargement!

hope it helps

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Which other congruency statements are correct?
Naddik [55]

Answer:

All are correct there are just disorganized.

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2 years ago
Compute the conditional probabilities P(A|B) and P(B|A).
Oksanka [162]

Answer:

Step-by-step explanation:

Good evening ,

P(A|B) = P(A∩B)/P(B)

P(B|A) = P(A∩B)/P(A)

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6 0
2 years ago
There are 60 players on a high school football team. The ratio of juniors and seniors to freshmen and sophmores on the team is 2
nata0808 [166]
You know that the ratio of J&S to F&So is 2:3. You need two numbers that have that same ratio to total 60 players.  When you multiply both numbers by 12, you have a ratio of 2:3 but the number of players is 24 to 36.  Thus, the total players is 60.  When looking at the ratio of Juniors to Seniors, the ratio remains 1:2, but must total 24 players.  Dividing the total players by 3, you can find where 1 part of the players equals 2 parts of the others.  Keeping that same ratio in mind, you are able to calculate that the ratio of Juniors to Seniors is 8:16 but when reduced, still remains a 1:2 ratio.
7 0
3 years ago
Read 2 more answers
A fitness center is interested in the average amount of time a client exercises in the center each week. Define the following in
Lubov Fominskaja [6]

Answer: C

Step-by-step explanation: As they are interested in the amount of time a client exercises in a week, the population would be all the clients that use the fitness center for a given week.

Clients that do not go on this week are not part of the population. The amount of time is what they want to know, so it cannot be the population.

7 0
3 years ago
Question 12<br> With steps please
34kurt

Answer:\ \boxed{5^2}

\sqrt[n]{a}=a^\frac{1}{n}\\\\\text{therefore}\\\\\sqrt5=5^\frac{1}{2}\\----------------\\25=5^2\\----------------\\78,125=5^7\\----------------\\\text{use}\\\\a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\----------------\\\\\dfrac{\sqrt5\times78,125}{25\times5^{\frac{7}{2}}}=\dfrac{5^\frac{1}{2}\times5^7}{5^2\times5^\frac{7}{2}}=\dfrac{5^{\frac{1}{2}+7}}{5^{2+3\frac{1}{2}}}=\dfrac{5^{7\frac{1}{2}}}{5^{5\frac{1}{2}}}=5^{7\frac{1}{2}-5\frac{1}{2}}=\boxed{5^2}

6 0
3 years ago
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