Question

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Answer 1

Answer: The area of the parallelogram ABCD = 32.4 sq. cm

Step-by-step explanation:

Given: In parallelogram ABCD, AB = 7.2 cm and the perpendicular drawn from C (altitude) on AB is 4.5 cm i.e.e height =4.5 cm.

Area of parallelogram = $(Base \times height)$

Then, Area of parallelogram ABCD = $7.2\times4.5$

= $32.4\ cm^2$

Therefore , the area of the parallelogram ABCD = 32.4 sq. cm