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Studentka2010 [4]
2 years ago
13

In cell B13, create a formula without a function using absolute references that subtracts the values of cells B5 and

Computers and Technology
1 answer:
chubhunter [2.5K]2 years ago
8 0

Answer:

The formula in Excel is:

=($B$6 - $B$5 - $B$7)* $B$8

Explanation:

Required

Use of absolute reference

To reference a cell using absolute reference, we have to include that $ sign. i.e. cell B5 will be written as: $B$5; B6 as $B$6; B7 as $B$7; and B8 as $B$8;

Having explained that, the formula in cell B13 is:

=($B$6 - $B$5 - $B$7)* $B$8

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If 209g of ethanol are used up in a combustion process, calculator the volume of oxygen used for the combustion at stp​
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a) The volume of oxygen used for combustion at STP is approximately 305 dm³

b) The volume of gas released during combustion at STP is approximately 508 dm³

Explanation:

The given chemical reaction equation for the burning of ethanol in air, is presented as follows;

2CH₃CH₂OH (l) + 6O₂ (g) → 4CO₂ (g) + 6H₂O

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The molar mass of ethanol, MM = 46.06844 g/mol∴

The number of moles of ethanol in the reaction, n = m/MM

∴ n = 209 g/(46.06844 g/mol) ≈ 4.537 moles

a) Given that 2 moles of ethanol, CH₃CH₂OH reacts with 6 moles of oxygen gas molecules, O₂, 4.54 moles of ethanol will react with (6/2) × 4.537 = 13.611  moles of oxygen

The volume occupied by one mole os gas at STP = 22.4 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, 'V', is given as follows;

V = 13.611 mol × 22.4 dm³/mole = 304.8864 dm³ ≈ 305 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, V = The volume of oxygen used for the combustion ≈ 305 dm³

b) The total number of moles of gases released in the reaction, is given as follows;

The total number of moles = (4.537/2) × (4 + 6) = 22.685 moles of gas

The total volume of gas released, V_T = The volume of gas released during the combustion at STP = 22.685 moles × 22.4 dm³/mole = 508.144 dm³ ≈ 508 dm³

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