Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
Answer:
A. the rational number system is closed under addition, but not multiplication
Step-by-step explanation:
may i pleaseee have brainliest
Answer:
1/6
Step-by-step explanation:
The answer is [ yes; ΔABC ~ ΔFGH by SAS Similarity ]
SAS Similarity states that two triangles have congruent corresponding angles and the corresponding sides have an identical ratio
The angle measure aren't given but the angles look to be the same.
To find the scale factor, divide.
12 / 8 = 1.5
15 / 10 = 1.5
The corresponding sides have an identical ratio.
This proves that option B is correct.
Best of Luck!
Answer:
Step-by-step explanation:
45x = 9*5*x
81 = 9*9
GCF = 9
Take 9 out using distributive property { a*b - c*b = b*(a-b)}
45x - 81 = 9*5x - 9*9
= 9*(5x - 9)
=9(5x-9)