thanks for free pints.........
Given
The demand function

To determine:
a) The revenue function.
b) The marginal revenue.
c) The marginal revenue when x=200.
d) The equation of tangent, and its derivation.
Explanation:
It is given that,

a) The revenue function is given by,

b) The marginal revenue function is,

c) The marginal revenue when x=200 is,

Hence, the marginal revenue is 3.84.
d) Let y=mx+c is the tangent.
Then,

That implies, for y=12.68, and x=200,

Hence, the equation of tangent is,
Replace the x in x^2 + 5x - 1 by x+3:-
g(x) =
(x+3)^2 + 5(x+3) - 1
= x^2 + 6x + 9 + 5x + 15 - 1
= x^2 + 11x + 23
- thats g(x)
Answer:
[-2, ∞]
Step-by-step explanation:
15 - √(x+2)
domain is any value as long as (x+2) is not-negative, since √ of a negative number has no Real solution.
x+2 ≥ 0 ⇒ x ≥ -2
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in