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2 years ago

5

The Baker Sends all his Bread in One Store. If he can pack up to 15 Loaves of Bread in a Box for Shipping, What is the Minimum n

umbers of Box Required to ship all the Loaves Baked in Two Weeks? Explain your reasoning?

1 answer:

GuDViN [60]2 years ago

4 0

I have no idea my brother just skip it

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The log: 20 can be written as

adoni [48]

Answer:

10+10

Step-by-step explanation:

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3 years ago

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What t chart matches the equation y=x^2-2

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The answer is y=xz-2

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3 years ago

Angle 1 and Angle 2 are supplementary. Angle 1 is 20 degree less than nine times the size of angle 2.

nadya68 [22]

Answer:

∠1=160° and ∠2=20°

Step-by-step explanation:

Let ∠1 = x

∠2 = y

as these two angles are supplementary their sum is 180

that x+y=180 ----(A)

Also given that ∠1 is 20 degree less than nine times the size of ∠2.

Hence

x=9y-20

putting value of x in A and solving for y

9y-20+y=180

10y=180+20

10y=200

y=10

Putting this y in A

x+10=180

x=160

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3 years ago

A freight elevator can hold a maximum weight of 3,500 pounds.

Brrunno [24]

Answer:

C

Step-by-step explanation:

$200 + 48c \leqslant 3500$

$48c \leqslant 3300$

$c \leqslant 68.75$

5 0

2 years ago

An athlete knows that when she jogs along her neighborhood greenway, she can complete the route in 10 minutes. It takes 20 minu

IgorLugansk [536]

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking rate, so athlete's jogging speed would be $x+5$ miles per hour.

$\text{Distance}=\text{Rate}\cdot \text{Time}$

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get $D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}$

$D_{\text{walking}}=\frac{x}{3}$

While jogging, we will get $D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}$

$D_{\text{jogging}}= \frac{(x+5)}{6}$

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

$\frac{x}{3}=\frac{x+5}{6}$

Cross multiply:

$6x=3x+15$

$6x-3x=15$

$3x=15$

$\frac{3x}{3}=\frac{15}{3}\\\\x=5$

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: $x+5\Rightarrow 5+5=10$

Therefore, athlete's jogging speed is 10 miles per hour.

3 0

3 years ago