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Ymorist [56]
3 years ago
12

Write an equation for the parabola whose vertex is at (3, 6) and which passes through (4, 4).

Mathematics
1 answer:
34kurt3 years ago
6 0

Answer:

<h3>            f(x) = -2 (x - 3)² + 6</h3>

Step-by-step explanation:

The vertex form of the equation of the parabola with vertex (h, k)  is:

f(x) = a(x - h)² + k

so the equation of parabola with the vertex (3, 6) is

f(x) = a(x - 3)² + 6  

passes through the point (4, 4) means: if x=4 then f(x)=4

4 = a(4 - 3)² + 6  

4 -6 = a(1)² + 6 -6

-2 = a

Therefore the equation of parabla is:

                                 <u> f(x) = -2 (x - 3)² + 6  </u>

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7 0
3 years ago
16) When diagonal WY is drawn in trapezoid WXYZ, why will Angle XYW and angle ZWY always be congruent?
IrinaVladis [17]
The answer to this question would be D
6 0
4 years ago
Please help with this
otez555 [7]

Step-by-step explanation:

multiply 455 by 0.20

convert percentage to decimal

20% = 0.20 ( multiply by 10^-2)

why does this work?

convert to a fraction

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4 0
3 years ago
If n is even, which of the following cannot be odd?
lys-0071 [83]
B) 3n
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3(4)
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4 0
3 years ago
What is the factor of<br> 7x2 - 60x + 32
Vedmedyk [2.9K]

7x2-60x+32

Final result :

(x - 8) • (7x - 4)
Step by step solution :

Step 1 :

Equation at the end of step 1 :

(7x2 - 60x) + 32
Step 2 :
5 0
3 years ago
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