All categories

3 years ago

Write the equation in y intercept form

Mathematics

1 answer:

Vadim26 [7]3 years ago

5 0

Answer:

y=-2x+4

Explanation:

Subtract 6x from both sides of the equation.

3y=12−6x

Divide each term by 3 and simplify.

Divide each term in 3y=12−6x by 3.

Cancel the common factor of 3.

Simplify

You might be interested in

An equation was used to predict possible weights of puppies at 6 months of age. The actual weights of the puppies are also liste

Nady [450]

The sum of the residuals is 26 hope that helps

7 0

2 years ago

Read 2 more answers

Boeing currently produces five models of airplanes for commercial sale. The airline that Lauren works for is rapidly expanding a

Sedbober [7]

Answer:

The number of combinations will she have to analyze is 10.

Step-by-step explanation:

We know that Boeing currently produces five models of airplanes for commercial sale. The airline that Lauren works for is rapidly expanding and would like to purchase three airplanes of different models to service various routes. We calculate the number of combinations will she have to analyze.

$C^5_3=\frac{5!}{3!(5-3)!}=\frac{5\cdot 4\cdot 3!}{3!\cdot 2\cdot 1}=10$

The number of combinations will she have to analyze is 10.

4 0

3 years ago

5/8=n-2/10<br><br> 9/x=10/x-7<br><br> p+9/p=3/10

lesya692 [45]

Download photo math for equations like this, it will also give you it step by step :)

4 0

3 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$