3 years ago

How many real solutions does a quadratic equation have if its discriminant is negative?

1 answer:

5 0

If the discriminant of a quadratic equation is negative, then the equation has no real solution.

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Brums [2.3K]

Answer:

y = 2 ± $\sqrt{x^2 - 4x + 4 + C}$

Step-by-step explanation:

Solve using separable equations

First put x and dx on the same side and do the same for y

(y-2)dy = (x-2)dx

Now you can integrate

$\frac{x^2}{2} +2x + C1 = \frac{y^2}{2} +2y\\$ + C1

Now we depending on how what ur instructor wants you may need to give exact solutions. We can do this by solving he quadratic equation for Y

Doing this you get:

y = 2 ± $\sqrt{x^2 - 4x + 4 + C}$

<em>Note C's were simplified.</em>

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