Force required to accelerate 10 kg object to 5.9 m/s/s ?
Mass = 10 kg
Acceleration = 5.9 m/s^2
Force = Mass * Acceleration
Force = 10 kg * 5.9 m/s^2
Force = 59 kg m /s^2 = 59 N
The force involved in the orbiting of the earth is gravity!
Answer:
1 joule = 0.737 foot-pound
Joule is the unit of work.
1 J = 1 N·m
In SI units
1 J = 1 kg· m/s²
0.737 foot-pound is the amount of work to raise 0.737 pounds one foot or raising one pound to 0.737 ft.
Answer:
480 mL
Explanation:
Ideal gas law states:
PV = nRT
At constant pressure, nR/P is constant. Therefore:
V / T = V / T
420 mL / 220 K = V / 250 K
V ≈ 480 mL
