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3 years ago

13

How do I find the product?

1 answer:

Leno4ka [110]3 years ago

4 0

Answer:

-5,3.................

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If a= 5, b= 8, and c= ½<br><br> 6a - 2b + bc

Rainbow [258]

Answer:

18

Step-by-step explanation:

6x5=30

2x8=16

8x1/2=4

30-16=14

14+4=18

8 0

3 years ago

Megan took out a loan for $500. The rate is 8%. how much does Megan owe in interest if she pays it back in 4.5 years

Arte-miy333 [17]

56272773829292929383847737373

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3 years ago

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Circle a has a radius of 3 and circle b has a radius of 11. if the idstance between the center of the circles in 17, find the le

Andrews [41]

Use Pythagorean Theorem:
a² + b² = c²
"a" is one side of the right triangle.
Its length is: radius of larger circle minus radius of smaller circle: (11 - 3 = 8)
The distance between the center of the circles creates the hypotenuse (17)
8² + b² = 17²
b² = 225
b = 15

Answer: the length of the common external tangent is 15.

3 0

3 years ago

Need help asap for geometry

kupik [55]

Answer:

35

Step-by-step explanation:

40=1/2(115-x)

80=115-x

-35=-x

x=35

4 0

3 years ago

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Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?

BaLLatris [955]

Answer:

$Vertex = (\frac{1}{2},\frac{7}{4})$

Step-by-step explanation:

Given

$f(x) = x^2 - x +2$

Required

The vertex

We have:

$f(x) = x^2 - x +2$

First, we express the equation as:

$f(x) = a(x - h)^2 +k$

Where

$Vertex = (h,k)$

So, we have:

$f(x) = x^2 - x +2$

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

$f(x) = x^2 - x +2$

$f(x) = x^2 - x + (-\frac{1}{2})^2+2 -(-\frac{1}{2})^2$

$f(x) = x^2 - x + \frac{1}{4}+2 -\frac{1}{4}$

Expand

$f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2 -\frac{1}{4}$

Factorize

$f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2 -\frac{1}{4}$

Factor out x - 1/2

$f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+2 -\frac{1}{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}$

$f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}$

Compare to: $f(x) = a(x - h)^2 +k$

$h = \frac{1}{2}$

$k = \frac{7}{4}$

Hence:

$Vertex = (\frac{1}{2},\frac{7}{4})$

8 0

3 years ago

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