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skad [1K]
3 years ago
13

How do I find the product?

Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0

Answer:

-5,3.................

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If a= 5, b= 8, and c= ½<br><br> 6a - 2b + bc
Rainbow [258]

Answer:

18

Step-by-step explanation:

6x5=30

2x8=16

8x1/2=4

30-16=14

14+4=18

8 0
3 years ago
Megan took out a loan for $500. The rate is 8%. how much does Megan owe in interest if she pays it back in 4.5 years
Arte-miy333 [17]
56272773829292929383847737373
6 0
3 years ago
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Circle a has a radius of 3 and circle b has a radius of 11. if the idstance between the center of the circles in 17, find the le
Andrews [41]
Use Pythagorean Theorem:
a² + b² = c²
"a" is one side of the right triangle.
Its length is: radius of larger circle minus radius of smaller circle: (11 - 3 = 8)
The distance between the center of the circles creates the hypotenuse (17)
8² + b² = 17²
       b² = 225
       b = 15

Answer: the length of the common external tangent is 15.

3 0
3 years ago
Need help asap for geometry​
kupik [55]

Answer:

35

Step-by-step explanation:

40=1/2(115-x)

80=115-x

-35=-x

x=35

4 0
3 years ago
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Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?
BaLLatris [955]

Answer:

Vertex = (\frac{1}{2},\frac{7}{4})

Step-by-step explanation:

Given

f(x) = x^2 - x +2

Required

The vertex

We have:

f(x) = x^2 - x +2

First, we express the equation as:

f(x) = a(x - h)^2  +k

Where

Vertex = (h,k)

So, we have:

f(x) = x^2 - x +2

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

f(x) = x^2 - x +2

f(x) = x^2 - x + (-\frac{1}{2})^2+2  -(-\frac{1}{2})^2

f(x) = x^2 - x + \frac{1}{4}+2  -\frac{1}{4}

Expand

f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2  -\frac{1}{4}

Factorize

f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2  -\frac{1}{4}

Factor out x - 1/2

f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2  -\frac{1}{4}

f(x) = (x - \frac{1}{2})^2+2  -\frac{1}{4}

f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}

f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}

Compare to: f(x) = a(x - h)^2  +k

h = \frac{1}{2}

k = \frac{7}{4}

Hence:

Vertex = (\frac{1}{2},\frac{7}{4})

8 0
3 years ago
Read 2 more answers
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