15 $ is the answer
3.75 x
4. = 15$
I'll presume the slash is the fraction bar and the questioner is asking about
![\dfrac{4a+12}{a+3}](https://tex.z-dn.net/?f=%5Cdfrac%7B4a%2B12%7D%7Ba%2B3%7D)
That always equals 4 except when ![a=-3](https://tex.z-dn.net/?f=a%3D-3)
So the restriction is
Answer: a ≠ -3
Answer:
true
Step-by-step explanation:
the bigger the number of a negative integer, the smaller the value become
Answer:
125/6(In(x-25)) - 5/6(In(x+5))+C
Step-by-step explanation:
∫x2/x1−20x2−125dx
Should be
∫x²/(x²−20x−125)dx
First of all let's factorize the denominator.
x²−20x−125= x²+5x-25x-125
x²−20x−125= x(x+5) -25(x+5)
x²−20x−125= (x-25)(x+5)
∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx
x²/(x²−20x−125) =x²/((x-25)(x+5))
x²/((x-25)(x+5))= a/(x-25) +b/(x+5)
x²/= a(x+5) + b(x-25)
Let x=25
625 = a30
a= 625/30
a= 125/6
Let x= -5
25 = -30b
b= 25/-30
b= -5/6
x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)
∫x²/(x²−20x−125)dx
=∫125/6(x-25) -∫5/6(x+5) Dx
= 125/6(In(x-25)) - 5/6(In(x+5))+C
Well the answer is 12-14=%58=x