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alukav5142 [94]
3 years ago
9

Please help me with my math ;-;

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0
I only know 1 & 4 .. 2 & 3 seem hard to me ..
X >7
X< -7
-
You might be interested in
One solution 19x+18=-19x+18
masya89 [10]

19x + 18 = -19x + 18

19x + 19x = 18 - 18

38x = 0

x = 0

3 0
3 years ago
What is the expression of 3^9
nordsb [41]
Well, 3^9 is the same thing as
3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3
So 3^9 is equal to 19,683
4 0
3 years ago
Read 2 more answers
Find the LCM of 6 and 15.<br> A) 6 <br> B) 15 <br> C) 30 <br> D) 90
erastovalidia [21]

Answer:

30

Step-by-step explanation:

the answer is 30 because if you count by 6 it would go 6,12,18,24,30,36,42 and if you go by 15 it would be 15,30,45,60,75,90..... and the only number that you see twice is 30 so the answer would be 30. Hope this helped...

3 0
3 years ago
Read 2 more answers
Questions are in the picture
gtnhenbr [62]

The closest point is (3.5, 1.9) and the distance is 1.96 units

<h3>How to determine the point and the distance?</h3>

The coordinate is given as:

(4, 0)

The equation of the function is

y = √x

The distance between two points is calculated using

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have the following points

(x1, y1) = (4, 0) and (x2, y2) = (x, 0)

This gives

d = √(x - 4)^2 + (√x - 0)^2

Evaluate the difference

d = √(x - 4)^2 + (√x)^2

Evaluate the exponent

d = √x^2 - 8x + 16 + x

Evaluate the like terms

d = √x^2 - 7x + 16

Next, we differentiate using a graphing calculator

d' = (2x - 7)/[2√(x^2 - 7x + 16)]

Set to 0

(2x - 7)/[2√(x^2 - 7x + 16)] = 0

Cross multiply

2x - 7 = 0

Add 7 to both sides

2x = 7

Divide by 2

x = 3.5

So, we have:

Substitute x = 3.5 in y = √x

y = √3.5

Evaluate

y = 1.9

So, the point is (3.5, 1.9)

The distance is then calculated as:

d = √(x2 - x1)^2 + (y2 - y1)^2

This gives

d = √(3.5 - 4)^2 + (1.9 - 0)^2

Evaluate

d = 1.96

Hence, the closest point is (3.5, 1.9) and the distance is 1.96 units

Read more about distance at:

brainly.com/question/23848540

#SPJ1

3 0
1 year ago
Use &gt;,&lt;,=.<br> 0.94___0.49
uranmaximum [27]
0.94>0.49 because 0.94 is the larger number.

5 0
3 years ago
Read 2 more answers
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