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guajiro [1.7K]
3 years ago
6

2.please I need help

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

9514 1404 393

Answer:

  1. 48°
  2. 60°
  3. 72°

Step-by-step explanation:

The sum of ratio units is 4+5+6 = 15, so each unit stands for 180°/15 = 12°. Multiplying the ratio units by 12° gives the angle values:

  4×12° : 5×12° : 6×12° = 48° : 60° : 72°

Angles 1 to 3 are 48°, 60°, 72°, respectively.

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Using ƒ(x) = 2x + 7 and g(x) = x − 3, find ƒ(g(-2)).
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Answer:

We conclude that:

f(g(-2)) = -3

Step-by-step explanation:

Given

  • f(x) = 2x + 7
  • g(x) = x-3

To determine

  • f(g(-2)) = ?

In order to determine f(g(-2)), first we need to determine g(-2)

so substituting x = -2 in g(x) = x-3

g(-2) = -2 - 3

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Thus,

f(g(-2)) = f(-5)

now substitute x = -5 in the function f(x) = 2x+7

f(x) = 2x+7

f(-5) = 2(-5) + 7

f(-5) = -10 + 7

f(-5) = -3

so

f(g(-2)) = f(-5) = -3

Therefore, we conclude that:

f(g(-2)) = -3

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3 years ago
How do you use a table of values to graph a question
stiv31 [10]

Answer:

You find x and y values.

Step-by-step explanation:

4 0
4 years ago
A customer from cavallaro's fruit stand picks a sample of 5 oranges at random from a crate containing 60 oranges, of which 6 are
notsponge [240]
Chances of one or more = 1 - chance of no rotten oranges

chance of no rotten oranges = 54/60 * 53/59 * 52/58 * 51/57 * 50/56
4 0
4 years ago
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X-2y=16 and x-y=8 its a system of equation. I don't know how to do this please help.
egoroff_w [7]
\left\{\begin{array}{ccc}x-2y=16\\x-y=8\end{array}\right\\\\\#1\ elimination\ method:\\\left\{\begin{array}{ccc}x-2y=16\\x-y=8&|change\ signs\end{array}\right\\\underline{+\left\{\begin{array}{ccc}x-2y=16\\-x+y=-8\end{array}\right}\ \ \ \ |add\ both\ sides\ of\ the\ equations\\.\ \ \ \ \ -y=8\to\boxed{y=-8}\\\\subtitute\ value\ of\ y=-8\ to\ the\ second\ equation\\\\x-(-8)=8\\x+8=8\ \ \ \ |subtract\ 8\ from\ both\ sides\\\boxed{x=0}\\\\Answer:\boxed{\boxed{\left\{\begin{array}{ccc}x=0\\y=-8\end{array}}}

\#\ subtitute\ method:\\\left\{\begin{array}{ccc}x-2y=16\\x-y=8&|add\ "y"\ to\ both\ sides\end{array}\right\\\left\{\begin{array}{ccc}x-2y=16&(1)\\x=y+8&(2)\end{array}\right\\\\subtitute\ (2)\ to\ (1)\\\\(y+8)-2y=16\\y+8-2y=16\\-y+8=16\ \ \ \ |subtract\ 8\ from\ both\ sides\\-y=8\to \boxed{y=-8}\\\\subtitute\ value\ of\ y=-8\ to\ (2)\\x=-8+8\\\boxed{x=0}\\\\Answer:\boxed{\boxed{\left\{\begin{array}{ccc}x=0\\y=-8\end{array}\right}}
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3 years ago
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Assume that y varies inversely as x. If y = -8 when x = -9, find y when x = 4.
IrinaVladis [17]
Y α 1/x

y = k/x  Where k is the constant of proportionality.

xy = k    Cross Multiplying.

k = xy

Recall  y= -8 when x = -9

k = -9 * -8 = 72

Finding y when x = 4.

k = xy

72 = 4y    Divide both sides by 4.

y = 72/4 = 18.

y = 18.
6 0
3 years ago
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