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3 years ago

What is the value of the product (3 - 2i)(3+2i)?

Mathematics

1 answer:

lions [1.4K]3 years ago

5 0

Answer:

Step-by-step explanation:

1. Distribute each term in the first binomial to each term in the second binomial, FOIL (first, outer, inner, last)

(3 - 2i) (3 + 2i)

9 + 6i - 6i - $4i^{2}$

2. Simplify

9 - $4i^{2}$

3. Solve for i. $i^{2}$ = -1

9 - 4 (-1)

9 + 4 = 13

hope this helps!

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#2 , #4 , #6 , #8 , #10 please

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6)
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$\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}$

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