If you wanted to use the numeric key pad to multiply 33 by 3, you would type ____

For which product would the producer keep a high profit margin and offer after-sales service?

Zina [86]

What are the products?

6 0

3 years ago

John would like to move from the city into the suburbs and has been saving up a large down payment for a home. which is the most

Murrr4er [49]

When we say suburban area, this is the area that is only a part of the city or a region that is distant from the city but not to the point that it becomes rural. So for John, the best way for him to save up in order to acquire a place to stay in the suburbs is to move first to the suburbs and rent a home for a year. This would give John enough time to decide whether he would like the suburban living and to look for a perfect location for his house.

8 0

3 years ago

Greedy Algorithm Design

Alik [6]

Answer:

The algorithm is as follows:

1. Start

2. Get the number of items (n)

3. Get the current price of the n items (a1, a2..... an)

4. Get the possible hiked price of the n items (b1, b2..... bn)

5. Calculate the difference between the current and hiked prices for each item i.e. $d_i = b_i - a_i$

6. Sort the differences in descending order (i.e. from the greatest to the least)

7. Buy items in this order of difference

8. Stop

Explanation:

The algorithm is self-explanatory; however, what it does is that:

It takes a list of the current price of items (say list a)

E.g: $a = [100, 150, 160]$

Then take a list of the hiked price of the items (say list b)

E.g: $b = [110, 180, 165]$

Next, it calculates the difference (d) between corresponding prices $d_i = b_i - a_i$

$d = [(110 - 100),(180-150),(165-160)]$

$d = [10,30,5]$

Sort the difference from greatest to lowest (as the difference is sorted, lists a and b are also sorted)

$d = [30,10,5]$

$a = [150, 100, 160]$

$b = [180, 110, 165]$

If there is no hike up to item k, the couple would have saved (i = 1 to d[k-1])

Assume k = 3

The couple would have saved for 2 item

$Savings = d[1] + d[2]$

$Savings = 30 +10$

$Savings = 40$

The saved amount will then be added to the kth item in list a i.e. a[k](in this case k = 3) in order to buy b[k]

Using the assumed value of k

$a[k] = a[3]$

$a[3] = 160$

$b[3] = 165$

Add the saved amount (40) to a[3]

$New\ Amount = 40 + 160$

$New\ Amount = 200$

This new amount can then be used to buy b[3] i.e. 165, then they save the change for subsequent items

8 0

3 years ago

For activities with output like below, your output's whitespace (newlines or spaces) must match exactly. See this note. Jump to

Vinvika [58]

Answer:

The program to this question can be given as:

Program:

#include<stdio.h>//include header file

int main() //defining main method

{

printf("Hello..! and please vote the answer."); //print value.

return 0;

}

Output:

Hello..! and please vote the answer.

Explanation:

In the given question some information is missing that is the message to be printed, In this code assume some message to be displayed, and the description to the above code as follows:

In the above code firstly header file is included for using a basic function like print method, input method, etc.
In the next line main method is defined, inside the main method a print function is used in this function a message is passed with a double-quote ("'). When the code will execute it will print the message that is given in the output section.

5 0

2 years ago

2. Write a program that calls creates an ArrayList of integer and calls the method minToFront described below. Print out the lis

Novosadov [1.4K]

Answer:

import java.util.ArrayList;

public class MinToFront {

public static void minToFront(ArrayList < Integer > list){

int miniIndex = 0;

for(int j=1; j<list.size(); j++){

if(list.get(miniIndex) > list.get(j))

miniIndex = j;

}

// moving min to front

int min = list.get(miniIndex);

list.remove(miniIndex);

list.add(0, min);

}

public static void main(String[] args) {

ArrayList<Integer> list = new ArrayList<>();

list.add(4); //value store in list

list.add(7); //value store in list

list.add(9); //value store in list

list.add(2); //value store in list

list.add(7); //value store in list

list.add(5); //value store in list

list.add(3); //value store in list

list.add(5); //value store in list

list.add(1); //value store in list

list.add(7); //value store in list

list.add(8); //value store in list

list.add(6); //value store in list

list.add(7); //value store in list

System.out.println(list);

minToFront(list);

System.out.println(list);

}

Output:

[1, 4, 7, 9, 2, 7, 7, 5, 3, 5, 7, 8, 6, 7]

Explanation:

Firstly,we define a method minToFront(), than set an integer variable "miniIndex" to 0, than set a for loop and apply the following condition and inside the loop we apply the if condition, set an integer variable "min" in which we store the value and than we set the following list [4, 7, 9, 2, 7, 7, 5, 3, 5, 1, 7, 8, 6, 7], after that print the list and than print an output.

3 0

3 years ago

If you wanted to use the numeric key pad to multiply 33 by 3, you would type _____.