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oee [108]
2 years ago
9

What must be included in an algebraic

Mathematics
1 answer:
Lemur [1.5K]2 years ago
8 0

Answer:

B. you need atleast one variable for an algebraic expression.

an equals sign would make it an algebraic equation,

just a coefficient and a variable is the most basic algebraic expression. you don't need anything other than those for an expression. you can have more than one number, and more than one operation, but they don't have to be there.

Step-by-step explanation:

i hope this helps :))

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Can someone tell me whats 3\4x5\6 is im dum
Anastaziya [24]

Answer:

15/24

Step-by-step explanation:

hope this helps u.

4 0
3 years ago
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A committee is formed consisting of one representative from each of the 4 departments (CS-IS-IT-SW) in the computer science coll
alexandr1967 [171]

Step-by-step explanation:

each department has 3 options for their representative.

and each of these options can be associated with the 3 options of the next department. and so on.

so, we have

3×3×3×3 = 3⁴ = 81

possibilities to firm that committee overall.

7 0
3 years ago
A table has 16 glasses on it. 7of the glasses are large. The rest are small. How many glasses are small?
kirill [66]
9? Unless it’s a trick question
5 0
3 years ago
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Check thepic plzz first answer brainliest
aleksandr82 [10.1K]

Answer:

Total Surface Area:  A = 88 square cm

Step-by-step explanation:

Volume V = 48 cubic cm

So this cuboidal box is actually a rectangular prism.

V =  L * W* H

L = length,   W = breadth,   H= height

With  L: W : H = 3: 2: 1

L:W = 3: 2

W: H = 2: 1

L/W  = 3/2,    L = (3/2)*W

W/H = 2/1 ,    W = 2*H

L = (3/2)*(2H) =  3H

So  :   V = L * W * H =  (3H) * (2H) * H  = 6 * H^3

48  =  6 * H^3

48/6 = 8 = H^3

H = cube-root(8) =  2 cm

so  ...

W = 2*H = 2*2 = 4 cm

L = (3/2)*W = (3/2)* 4 = 6 cm

Total Surface Area:  A = 2*LW  + 2*LH + 2*WH

A = 2*(6 * 4)  +  2*(6 * 2)  + 2*(4 * 2)

A = 2*24  + 2*12 + 2*8

A = 48 + 24 + 16

A = 48 + 40

A = 88 square cm

4 0
3 years ago
How to graph y=2^x+3
Mashcka [7]

Answer:

  see below

Step-by-step explanation:

It is usually convenient to choose small exponents when graphing an exponential function. You can get a reasonable idea of the shape of the curve using x-values with a magnitude of 3 or less.

The exponential term 2^x has a horizontal asymptote of y=0 for large negative values of x. Adding 3 to that term shifts the horizontal asymptote up to y=3. Of course, everything else is shifted up the same amount.

You know that ...

  2^-1 = 1/2

  2^0 = 1

  2^1 = 2

  2^2 = 4

Adding 3 to these values will give you points on the graph for x=-1 to 2.

7 0
3 years ago
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