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SashulF [63]
4 years ago
14

Select all the equations that describe each situation and then find the solution.Han's house is 450 meters from school. Lin hous

e 135 meter closer to school.How far is lin's house from school?
Mathematics
1 answer:
solniwko [45]4 years ago
4 0
<h3>The actual distance form Lin's house to school is 315 m.</h3>

Step-by-step explanation:

Here, given the distance between Han's house and school = 450 m

Lin's  house is 135 meter closer to school.

Let us assume that Lin's house k meters from school.

So, the actual distance from Lin's home + 135 m =Distance of Han's house from school.

or, k + 135 m = 450 m

⇒ k = 450 m - 135 m = 315 m

So, the actual distance form Lin's house to school is 315 m.

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Nadia is a stockbroker.She earns 11% commission each week, She sold $7,500 worth stocks.How much did she make last week in commi
Monica [59]

Answer:

a). Nadia made a total of $825 last week in commission sales

b). The total amount Nadia in commission in 2011=$42,900

Step-by-step explanation:

Step 1

Express the amount in commission she earns from her sales as follows;

C=S×r

where;

C=commission earned

S=total value of stock sales

r=commission rate

In our case;

C=unknown

S=$7,500

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replacing;

C=11% of 7,500

C=(11/100)×7,500

C=0.11×7,500=825

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b). To express the total amount she made in 2011, we derive the formula below;

Total amount (2011)=Average weekly commission×number of weeks in 2011

where;

Average weekly commission=$825

number of weeks in 2011=52

replacing;

Total amount (2011)=(825×52)=42,900

The total amount Nadia in commission in 2011=$42,900

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3 years ago
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Answer:

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Coz,there are 4 triangle we multiple by 4

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