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bekas [8.4K]
3 years ago
10

Find the equation of the line shown

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0

Answer:

The equation of the line is:

y = x + 1

Step-by-step explanation:

The equation of a line has the following format:

y = mx + b

In which m is the slope(suppose we have two points, the slope is the change in y divided by the change in x).

b is the y-intercept(the value of x when y = 0).

In this question:

When x = 0, y = 1, so b = 1

Passes through the points (0,1) and (1,2). So the slope is

m = \frac{2-1}{1-0} = 1

The equation of the line is:

y = x + 1

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7a+5r

Step-by-step explanation:

5a + 1r + 2a + 4r

add like terms

7a+5r

hope that helps

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2 years ago
If log (m + n) = log m+log n, show that m =n/n-1​
Sedbober [7]

log (m + n) = log m+ log n and proved it m =n/n-1​

Given;

If log (m + n) = log m+ log n

To show that the m =n/n-1​

Now, According to the question:

We know that,

Log (m + n) = log m + log n

Log (m + n ) = log (mn).                 [log a + log b = log ab ]

Cancelling the log on both sides.

then,

m + n = mn

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log (m + n) = log m+ log n and proved it m =n/n-1​

What is Logarithm?

A logarithm is the power to which a number must be raised in order to get some other number (see Section 3 of this Math Review for more about exponents). For example, the base ten logarithm of 100 is 2, because ten raised to the power of two is 100: log 100 = 2.

Learn more about Logarithm at:

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1 year ago
Mathematical Statistics with Applications Help Homework
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7.43: Let X denote the random variable for height and \overline X for the sample mean. Then if \mu is the mean of

So the probability that the difference between the sample and population means does not exceed 0.5 inch is

P(|\overline X-\mu|\le0.5) = P\left(\left|\dfrac{\overline X-\mu}{0.25}\right|\le\dfrac{0.5}{0.25}\right) = P(|Z|\le 2) \approx \boxed{0.95}

per the empirical or 68/95/99.7 rule.

7.44: For a sample of size <em>n</em>, the sample standard deviation would be \frac{2.5}{\sqrt n}. We want to find <em>n</em> such that

P(|\overline X-\mu| < 0.4) = 0.95

Comparing to the equation from the previous part, this means we would need

\dfrac{0.4}{\frac{2.5}{\sqrt{n}}} = 0.16\sqrt n = 2 \implies \sqrt n = 12.5 \implies n = 156.25

so a sample of at least 157 men would be sufficient.

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