3 years ago

S

Mathematics

1 answer:

Korolek [52]3 years ago

8 0

Answer:

Step-by-step explanation:

If its right let me know I think this is right

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What are the zeroes of f(x) = x2 − 6x + 8? (4 points) x = −4, 2 x = −4, −2 x = 4, 2 x = 4, −2

babymother [125]

Hey there! :)

Answer:

Third option. x = 2, and x = 4.

Step-by-step explanation:

Find the zeros of this quadratic equation by factoring:

f(x) = x² - 6x + 8

Becomes:

f(x) = (x - 4)(x - 2)

Set each factor equal to 0 to solve for the roots;

x - 4 = 0

x = 4

x - 2 = 0

x = 2

Therefore, the zeros of this equation are at x = 2, and x = 4.

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given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$

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What is the following product? 3 sqrt 4 * sqrt 3

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Answer:

6 sqrt 3

Step-by-step explanation:

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Which equation is true for x = –6 and x = 2?

schepotkina [342]

Answer:

$x^2+4x-12=0$

Step-by-step explanation:

If a equation has two zeros x=a and x=b then equation can be written as

$(x-a)(x-b)=0$

similarly if a equation has two zeros at x = −6 and x = 2

then equation can be written as

$(x+6)(x-2)=0$

$x^2+6x-2x-12=0$

$x^2+4x-12=0$

Therefore $x^2+4x-10$ is required equation

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