Angle A = 130° and Angle B = 110°
Solution:
Given ABCD is a trapezoid with ∠C = 70° and ∠D = 50°
If ABCD is a trapezoid, then AB is parallel to CD.
AD is a transversal to AB and CD and
BC is a tranversal to AB ad CD.
Sum of the interior angles on the same side are supplementary.
∠A + ∠D = 180°
⇒ ∠A + 50° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠A = 180° – 50°
⇒ ∠A = 130°
Similary, ∠B + ∠C = 180°
⇒ ∠B + 70° = 180°
Subtract 50° on both sides to equal the expression.
⇒ ∠B = 180° – 70°
⇒ ∠B = 110°
Hence, angle A = 130° and angle B = 110°.
1/2(2.5x)=40
2.5x=80
x=32
the number is 32
Answer:
Step-by-step explanation:
2b^2 - 3b + 4a^2........a =-6 and b = 8
now we sub
2(8^2) - 3(8) + 4(-6^2)
2(64) - 24 + 4(36)
128 - 24 + 144
272 - 24
248 <==
Answer: 8.1ft
Step-by-step explanation:
It may help to draw it out but for this question you would have to use pythagoras' theorem.
The formula for the shorter side is a²=c²-b²
The height of this triangle is 4ft (b) and the hypotenuse (the diagonal that stretches from the top to the bottom) is 9ft (c).
When we put the numbers in the formula you get a²=9²-4²
9²=81
4²=16
a²=81-16
a²=65
Then because we want to find a on it's own you would have to square root 65 which is 8.1 (to the nearest tenth)
