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olga55 [171]
3 years ago
14

In mom's car, the number of miles driven is proportinal to the number of gallons of gas used.

Mathematics
1 answer:
DerKrebs [107]3 years ago
7 0
For number 1 the answer is 112

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A recent national survey found that high school students watched an average (mean) of 7.8 movies per month with a population sta
notka56 [123]

Answer:

Step-by-step explanation:

Given that :

Mean = 7.8

Standard deviation = 0.5

sample size = 30

Sample mean = 7.3 5.4772

The null and the alternative hypothesis is as follows;

\mathbf{ H_o: \mu  \geq  7.8}

\mathbf{ H_1: \mu  <  7.8}

The test statistics can be computed as :

z = \dfrac{X- \mu}{\dfrac{\sigma}{\sqrt{n}}}

z = \dfrac{7.3- 7.8}{\dfrac{0.5}{\sqrt{30}}}

z = \dfrac{-0.5}{\dfrac{0.5}{5.4772}}

z = - 5.4772

The p-value at  0.05 significance level is:

p-value = 1- P( Z < -5.4772)

p value = 0.00001

Decision Rule:

The decision rule is to reject the null hypothesis if  p value is less than 0.05

Conclusion:

At  the 0.05 significance level,  there is sufficient information to reject the null hypothesis. Therefore ,we  conclude that college students watch fewer movies a month than high school students.

8 0
3 years ago
The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room
Alexandra [31]

Answer:

\bar x = 260.1615

\sigma = 70.69

The confidence interval of standard deviation is: 53.76 to 103.25

Step-by-step explanation:

Given

n =20

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}

\bar x = \frac{5203.23}{20}

\bar x = 260.1615

\bar x = 260.16

Solving (b): The standard deviation

This is calculated as:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}

\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}\sigma = \sqrt{\frac{94938.80}{19}}

\sigma = \sqrt{4996.78}

\sigma = 70.69 --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

c =0.95

So:

\alpha = 1 -c

\alpha = 1 -0.95

\alpha = 0.05

Calculate the degree of freedom (df)

df = n -1

df = 20 -1

df = 19

Determine the critical value at row df = 19 and columns \frac{\alpha}{2} and 1 -\frac{\alpha}{2}

So, we have:

X^2_{0.025} = 32.852 ---- at \frac{\alpha}{2}

X^2_{0.975} = 8.907 --- at 1 -\frac{\alpha}{2}

So, the confidence interval of the standard deviation is:

\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} } to \sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }

70.69 * \sqrt{\frac{20 - 1}{32.852} to 70.69 * \sqrt{\frac{20 - 1}{8.907}

70.69 * \sqrt{\frac{19}{32.852} to 70.69 * \sqrt{\frac{19}{8.907}

53.76 to 103.25

8 0
2 years ago
I need answers to all please
valina [46]

Answer:

Step-by-step explanation:

2a.x=10+5

b. x=11-7

C. x=5*2

4 0
3 years ago
Read 2 more answers
Line segment RS is graphed with its end points at (1, 3) and (7, 11) If RS is dilated by a
Alchen [17]
For the answer to the question above, <span>what is the combined length of
the original line segment and its dilated image?
</span>RS = 10 
image R'S' = 20 
---> 10+20=30
I hope my answer helped you. Feel free to ask more questions. have a nice day!
7 0
2 years ago
Lilah completed the division problem below.
victus00 [196]
A - False

B - True

C - True

D - False

E - True

-----
7.84 / 2 = 3.92
6 0
3 years ago
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