Ford Family consists of:
a) 2 adults
The price of ticket for each adult is $18.55. This can be approximated to $19 if we round it to nearest dollar. So the price of ticket for 2 adults will be 2 x 19 = $38
b) 3 children between ages 2 and 10.
Ticket for each child between ages 2 - 10 is $12.59 which can be approximated to $13. So ticket price for 3 children will be 3 x 13 = $39
c) 2 children below the age of 2.
Ticket price for each child is $6.54 which can approximated as $7. So ticket price for 2 children will be 2 x 7 = $14
The estimated total amount due on the family equals = 38 + 39 + 14 = $91
In each of the 3 cases we rounded up the values. So this means the actual amount must be slightly lesser than $91. The actual bill was $87.95 which is close to $91 and lesser than it. Hence we can conclude that $87.95 is the correct amount due for Ford Family.
Answer:
0.048 is the probability that more than 950 message arrive in one minute.
Step-by-step explanation:
We are given the following information in the question:
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.
Let X be the number of messages arriving at a multiplexer.
Mean = 15
For poison distribution,
Mean = Variance = 15

From central limit theorem, we have:
where n is the sample size.
Here, n = 1 minute = 60 seconds
P(x > 950)
Calculation the value from standard normal z table, we have,

0.048 is the probability that more than 950 message arrive in one minute.
Find slope by calculating rise (change in y) over run (change in x).
1-(-3)/-4-0
4/-4
-1
Final answer: A
The logic is there are six sides to each die, so for each number on one die you can pair with six different numbers on the other die. Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12.
Answer:
C
Step-by-step explanation:
16, 8, 4, 2, …
a = 16
r = 8/16 = ½
f(x) = 16 × (½)^(x - 1)