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Aleonysh [2.5K]
3 years ago
14

How to calculate 146 divided by 397 step by step to get the result 0,3377

Mathematics
1 answer:
topjm [15]3 years ago
5 0

it just keeps going . You keep adding the zero and subtracting.

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Enter the value of w so the expression -5 +0.6W is equivalent to w (2.5 – 0.3w)​
NeX [460]

9514 1404 393

Answer:

  w = -2 or 8 1/3

Step-by-step explanation:

Setting the two expressions equal makes a quadratic equation:

  -5 +0.6w = w(2.5 -0.3w)

  0.3w^2 -1.9w -5 = 0 . . . . . . subtract the right-side expression

  3w^2 -19s -50 = 0 . . . . . . . multiply by 10 to give integer coefficients

  (3w -25)(w +2) = 0 . . . . . . . factor

We can use the zero product rule to find the solutions. The product will be zero only if a factor is zero.

  3w -25 = 0   ⇒   w = 25/3 = 8 1/3

  w +2 = 0   ⇒   w = -2

The values of w that make the two expressions equivalent are -2 and 8 1/3.

8 0
3 years ago
I really really really really really need help on the questions that are in that picture I don't understand it all in a super bi
kobusy [5.1K]
5=1/12
6=1/11
______________________
3 0
4 years ago
Expanding logarithmic Expression In Exercise,Use the properties of logarithms to rewrite the expression as a sum,difference,or m
wel

Answer:

\frac{1}{2}ln(2x)-\frac{1}{2}ln(x^2-1)

Step-by-step explanation:

In 2x/(x^2 - 1)1/2

ln(\frac{2x}{x^2-1} )^\frac{1}{2}

Apply the property of natural log

ln x^m = m ln(x) move the exponent before ln

ln(\frac{2x}{x^2-1} )^\frac{1}{2}

\frac{1}{2}ln(\frac{2x}{x^2-1})

ln(m/n)= ln m - ln n

\frac{1}{2}(ln(2x)-ln(x^2-1))

multiply 1/2 inside the terms

\frac{1}{2}ln(2x)-\frac{1}{2}ln(x^2-1)

6 0
3 years ago
What's the GCF of 12a^2b^6, 28a^4 and 42ab^3? How did you find your answer?
8090 [49]

12a^2b^6=(2a)(6ab^6)\\\\28a^4=(2a)(14a^3)\\\\42ab^3=(2a)(21b^3)\\\\GCF(12a^2b^6,\ 28a^4,\ 42ab^3)=2a

6 0
3 years ago
In the equation y= -2x what are the possible values of y?
cestrela7 [59]
Y depends on x. And x are the real numbers.

Hope this helps!
8 0
3 years ago
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