what does the phrase “If your actions inspire others to dream more, learn more, do more and become more, you are a leader.” mean

In the poem called ''The Poison Tree'': How does Blake’s use of figurative language relate to themes of the play? Provide textua

Tasya [4]

Answer:

William Blake´s use of figurative language tells us that his hatred grew and grew as an apple tree and his enemy (his foe) stretched beneath the tree.

Explanation:

It makes us aware what bad feelings can cause in other´s peoples´ lives and in our own, if we try to conceal them or not to show them. They will always arise in probably dangerous forms for both, the reciever and the beholder.

5 0

2 years ago

What does hyper-masculine military subculture mean?

zavuch27 [327]

Hypermasculinity is a psychological term for the exaggeration of male stereotypical behavior, such as an emphasis on physical strength, aggression, and sexuality. This term has been used pejoratively by some scholars.

8 0

3 years ago

In mother to son who is the speaker

padilas [110]

Answer:

definitely the mother

Explanation:

4 0

3 years ago

Read 2 more answers

Please help! i need some help lol

Ostrovityanka [42]

I think the answer is b. hope it's right

8 0

3 years ago

I will make you brainlist if you help me the 2 question by explain them i swear i will make you brainlist

Xelga [282]

★ Formula Applied :

$\begin{gathered}\sf \bullet\ \; cos^2x-sin^2x=cos2x\\\\\to\ \sf \pink{sin^2x-cos^2x=-cos2x}\end{gathered}$

$\begin{gathered}\bullet\ \; \sf sin2x=2.sinx.cosx\\\\\to \sf \blue{sinx.cosx=\dfrac{sin2x}{2}}\end{gathered}$

$\displaystyle \bullet\ \; \sf \int \dfrac{dx}{x}$

$\bullet\ \; \sf \ln (ab)=\ln a+\ln$

★ Explanation :

$\begin{gathered}\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}dx\\\\\to \sf \int \dfrac{-cos2x}{\frac{sin2x}{2}}dx\\\\\to \sf \int \dfrac{-2cos2x}{sin2x}dx\end{gathered}$

Lets use substitution method ,

Let , u = sin2x

⇒ du = 2.cos2x.dx

$\begin{gathered}\to \displaystyle \sf \int \dfrac{-du}{u}\\\\\to \sf -\int \dfrac{du}{u}\\\\\to \sf -ln|u|\\\\\end{gathered}$

$\to \sf \red{-ln|sin2x|+c}$

$\to \sf - \ln |2sinx.cosx|+c$

$\to \sf - \ln |sinx.cosx|+(\ln 2+c)$

$\leadsto - \sf \red{\ln |sinx.cosx|+c}\ \; \bigstar$

★ Alternate Method :

$\displaystyle \sf \int \dfrac{sin^2x-cos^2x}{sinx.cosx}$

$\displaystyle \to \sf \int \left( \dfrac{sin^2x}{sinx.cosx}-\dfrac{cos^2x}{sinx.cosx}\right)dx$

$\begin{gathered}\displaystyle \to \sf \int \left( \dfrac{sinx}{cosx} -\dfrac{cosx}{sinx} \right)dx\\\\\to\ \sf \int (tanx-cotx)dx\\\\\to \sf \int tanx.dx-\int cotx.dx\\\\\to \sf ln|secx|-ln|sinx|+c\end{gathered}$

$\to \sf ln\left| \dfrac{secx}{sinx}\right|+c$

$\begin{gathered}\to \sf ln\left| \dfrac{1}{sinx.cosx} \right|+c\\\\\end{gathered}$ ]

$\leadsto \sf \pink{-ln|sinx.cosx|+c}\ \; \bigstar$

4 0

2 years ago