Answer:
the range for f(x) = (x-4) (x-2) is [-1,∞)
Step-by-step explanation:
all real numbers greater than or equal to -1
The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
Answer:
radians
Step-by-step explanation:
Arc length and radius is given. So, we need to know the arc length formula for a circle.
That is:

Where s is the arc length
r is the radius
is the angle (IN RADIANS)
We have:
s = 15.5
r = 9
Now, we substitute and find the angle:

The angle, in radians, in 1.72
Answer:

Step-by-step explanation:
We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).
The given line can be expressed as:

We can see the slope of this line is m1=-3/2.
The slopes of two perpendicular lines, say m1 and m2, meet the condition:

Solving for m2:



Now we know the slope of the new line, we use the slope-point form of the line:

Where m is the slope and (h,k) is the point. Using the provided point (-5,2):

Answer:

Step-by-step explanation:
x^2 + 1 = 4
x^2 = 3
