Answer:
(f+g)(x)=2^x-5x+1 and
(f-g)(x)=2^x-x-1
Step-by-step explanation:
(f+g)(x)=2^x-3x+1-2x
=2^x-5x+1
(f-g)(x)=2^x-3x-1+2x2x
=2^x-x-1
<u>Expression Form</u>
(3-7)*n+5
n=Unknown Number
Just follow this operation.
Find the two perfectly squared factors the multiple to your number.
Take the square root of those perfect factors then multiple them.
Answer:
x=2 and y=1
Step-by-step explanation:
Rewrite equations:
y=−x+3;y=x−1
Step: Solve
y=−x+3
Step: Substitute−x+3foryiny=x−1:
y=x−1
−x+3=x−1
−x+3+−x=x−1+−x(Add -x to both sides)
−2x+3=−1
−2x+3+−3=−1+−3(Add -3 to both sides)
−2x=−4−2x−2=−4−2
(Divide both sides by -2)
x=2
Step: Substitute2forxiny=−x+3:
y=−x+3
y=−2+3
y=1(Simplify both sides of the equation)
Hope this Helps you :)