Two sides are 34 and 14.
The third side can't be longer than (34 + 14) = 48, because the 34 and the 14
together could not reach from one end of it to the other.
The third side also can't be shorter than 20, because the 20 and the 14 together
could not reach from one end of the 34 to the other.
So 18 doesn't work. (18 + 14) = 32 ... they couldn't cover the 34 .
Answer:your answer to this prob,problem, is c) $108.75
Step-by-step explanation:
Answer:
q=4p-14
Step-by-step explanation:
5q-4p+6=4q-8
5q-4q-4p=-8-6
q-4p=-14
q=-14+4p
q=4p-14
Answer:
(-2,21)
Step-by-step explanation:
2 days ago, Paulo's commute time was halfway between his commute times 8 and 9 days ago.
8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.
9 days ago means that x-coordinate -9 represents this day. Count 9 units to the left and find that when x = -9, y = 18 minutes.
Find halfway commute time between points (-8,24) and (-9,18):
![y=\dfrac{24+18}{2}=\dfrac{42}{2}=21,](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B24%2B18%7D%7B2%7D%3D%5Cdfrac%7B42%7D%7B2%7D%3D21%2C)
then coordinates that Paulo should graph are
(-2, 21)
(-2 means 2 days ago, 21 is the halfway)
Answer:
Simple, no. This would not be enough.
Step-by-step explanation:
This is because you mentioned that there are 20 students and each of them needed 2 plates. So, there would need to be at least 40 plates. Forks seem irrelevant in this question but if the teacher has 8 plates in 1 box and another 8 in the second box, that would sum up to 16 plates that are available. And the fact that the box doesn't even include the other items, should hint the lack of items available for the students.
This question seemed worded differently. But tried my best. :)