Answer:
7/12
Step-by-step explanation:
Divide both the numerator & denoniminator by 7.
49 / 7 = 7
84 / 7 = 12
7/12
Answer:
-(m-4)(b-3)
Step-by-step explanation:
Add and subtract the second term to the expression and factor by grouping
Answer:
<em>Option D: 159 3/8 cm^3 </em>
Step-by-step explanation:
1. Let us rewrite the dimensions, and the options to make this a little more clear ~ (dimensions) 5 cm, 8 1/2 cm, 3 3/4 cm ⇒ (options) 17 1/4 cm^3, 18 3/4 cm^3, 27 1/4 cm^3, and 159 3/8 cm^3
2. To find the volume of most 3-dimensional figures, you would have to multiply the Base * height, so for a rectagular prism ⇒ <em>Base * height = length * width * height</em>
3. Substitute and compute the volume through algebra:
5 cm * 8 1/2 cm * 3 3/4 cm =
5 cm * 17/2 cm * 15/4 cm =
85/2 cm^2 * 15/4 cm =
1275/8 cm^3 =
<em>159 3/8 cm^3</em>
4. This means that the<em> Volume of the Rectangular Prism = 159 3/8 cm^3 (Option D)</em>
An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to... An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to...
Answer:
Step-by-step explanation:
So what we should do is first expand. What I did was I did it one step at a time, starting with (2x+5)(2x+5). This gave me 
. I then continued to do this, until I got 
. Then you asked me what this would be subtracted from 1. So, what I did was set it so that it would follow this rule, making it
.
After this, I just simplified.
