What is the midpoint of (-3,-7) and (9,8)

Mathematics

1 answer:

Sliva [168]3 years ago

4 0

Hope this will help you. It is a little hard to explain.

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Marking as brainliest !!!!

stepan [7]

Step-by-step explanation:

The diameter of the circle is 4 inches so its radius r is 2 inches. The area of the circle is

$A = \pi r^2 = \pi(2\:\text{in})^2 = 12.57\:\text{in}^2$

The circumference C of the circle is

$C = 2\pi r = 2\pi(2\:\text{in}) = 12.57\:\text{in}$

8 0

2 years ago

An airplane is 1440 above a buoy in the ocean. The buoy is 15 miles away from the mainland What is the diagonal distance in mite

Crazy boy [7]

Answer:

1440.08 mi

Step-by-step explanation:

Pythagorean Theorem:

$\sqrt{1440^{2}+15^{2} }$ = 1440.08

6 0

2 years ago

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

3 years ago

When adding or subtracting two decimals, what is the first thing you must do

polet [3.4K]

Line up the decimals

5 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!<br><br> Factor.<br><br> 64x^9 − 125y^6

shepuryov [24]

$Identity: \\ \boxed{ {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2}) } \\ \\ 64 {x}^{9} - 125 {y}^{6} \\ \\ = {(4 {x}^{3} )}^{3} - {(5 {y}^{2} )}^{3} \\ \\ = (4 {x}^{3} - 5 {y}^{2} )( \: {(4 {x}^{3} )}^{2} + 4 {x}^{3} \times 5 {y}^{2} + {(5 {y}^{2} )}^{2} \: ) \\ \\ = (4 {x}^{3} - 5 {y}^{2} )(16 {x}^{6} + 20 {x}^{3} {y}^{2} + 25 {y}^{4} )$

7 0

3 years ago