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3 years ago

6

PLEASE SOMEONE HELP NOWWWW.

2 answers:

yanalaym [24]3 years ago

8 0

Answer:

1.45 miles per minute

Step-by-step explanation:

The question asked it to be presented in miles per minute so divide 1000 by 60 which will give us 50/3. We then multiply that with cos(85) which will give us the final answer of 1.45.

dolphi86 [110]3 years ago

3 0

Answer:

Step-by-step explanation:

If the missile was going 900 mph and we are trying to find the horizontal velocity

This could be 3.88, and rounding it to the nearest hundredth would be 3.90 miles per minute

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A pigeon can fly 84 kilometers per hour. how long does the pigeon take to fly 7 kilometers?

Leviafan [203]

84 kilometers ... 1 hour
7 kilometers ... x hours = ?

If you would like to know how long does the pigeon take to fly 7 kilometers, you can calculate this using the following steps:

84 * x = 1 * 7
84 * x = 7 /84
x = 7/84
x = 1/12 hour

Result: A pigeon can fly 7 kilometers in 1/12 hour.

6 0

3 years ago

Read 2 more answers

A salad dressing recipe requires at least 8 oz of oil to be combined with some combination of vinegar and lemon juice in a 16 oz

valentina_108 [34]

Let x represent the number of ounces of vinegar

Let y represent the number of ounces of lemon juice

Oil required = 8 oz

Container can hold = 16 oz

So the inequality equation will be :

$x+y+8\geq16$

6 0

3 years ago

Tyler had $65.40 in his checking account. Then he wrote checks on the account for $20.38, $11.48, and $19.50. What is the balanc

andrew-mc [135]

money going out (20.38+11.48+19.50) =51.36

balance - out = new balance

65.40-51.36 =

14.04

new balance = 14.04

4 0

3 years ago

What is the simplest form of the expression 6x(x − 4) − 16x2 − (9x − 1)

BigorU [14]

If the term in the middle is 16x^2

6x^2-24x-16x^2-9x+1 =

-10x^2-33x+1

5 0

3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0

3 years ago

Read 2 more answers