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Solnce55 [7]
3 years ago
14

13 NEED HELP ASAP WILL GIVE BRAINLY

Mathematics
2 answers:
attashe74 [19]3 years ago
8 0

Answer:

A. Similar; congruent angles

Step-by-step explanation:

e-lub [12.9K]3 years ago
6 0

Answer:

The first statement is true because they have congruent angles.

The side length does not matter here because it's useless unless you're trying to find the perimiter of a triangle, which has a completely different algorithm. It is called the Pythagorem Theorum. I just learned the Pythagorem Theorum last class, and it isn't too difficult once you get the hang of it. Wow I went off course. Anyways I hope this helps!

Step-by-step explanation:

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Type a digit that makes this statement true.<br> 7,176,260 is divisible by 3.<br> Submit
Margarita [4]

Answer:

1, 4 or 7

Step-by-step explanation:

The divisibility rule/shortcut for 3 is that the sum of its digits is divisible by 3. So, you currently have 29 (7+1+7+6+2+6+0), and you have to make that number divisible by 3.

adding 1 gets you 30, which we know is divisible by 3.

then, instead of trying every digit, we can note that

30 , 33 , 36 , 39 ....

are divisible by 3.

But the most we can add to the sum of 29 is 9 (because that is the highest digit possible)--so numbers above 38 are irrelevant

so, we want to find out if we can make 29 into 30, 33, or 36

adding 1 to 29 = 30

adding 4 to 29 = 33

adding 7 to 29 = 36

So, by making the first digit 1 , 4 , or 7, you make the number divisible by 3 (making the sentence true)

8 0
2 years ago
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Which is the best estimate of the sum of 356 and 71, IF each number is rounded to the nearest ten?
xxMikexx [17]
/ 357 + 71= 427 you’ve got to add it to get the sum of the numbers together
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3 years ago
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√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1
Snowcat [4.5K]

Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}


\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s

7 0
3 years ago
Don’t be all up on me like that
Lelechka [254]

Sucks </3

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The reasonable amount of time it would take for him to run all five blocks is 19 minutes
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