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3 years ago

Lana wants to graph the height of an amusement park ride as it travels along the track.

Mathematics

2 answers:

likoan [24]3 years ago

6 0

Ok I got this it is A

dalvyx [7]3 years ago

3 0

I can’t do this for you, you have to drag the segments into the boxes. The fifth over is A. then you do the first line segment. Then the third. for D you do the fifth over

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Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

3 years ago

Please help me with this question

Lyrx [107]

Answer:

Step-by-step explanation:

Here is a site to help you...that my teacher showed me...when you search it it will show this...just click graphing calculator

desmos.com

5 0

3 years ago

The volleyball team at West View High School is comparing T-shirt companies where they can purchase their practice shirts. The t

Alex73 [517]

Answer:

Q#1.total number of T-shirts for total cost to be equal=10

Q#2.For the total cost to be the same for both companies, the volleyball team would need to purchase 10 T-shirts from each company

Q#3.total of $105 for each company.

Step-by-step explanation:

Q#1

two functions are given

y=10.5x

y=7.5x+30

where y represents cost and x represents number of shirts

we have to find number of shirts to be purchased from each company keeping cost equal

hence we will write

10.5x=7.5x+30

10.5x-7.5x=30

3x=30

x=30/3

x=10

Number of shirts to be equal cost price is 10

Q#2

two functions are given

y=10.5x

y=7.5x+30

where y represents cost and x represents number of shirts

we have to find number of shirts to be purchased from each company keeping cost equal

hence we will write

10.5x=7.5x+30

10.5x-7.5x=30

3x=30

x=30/3

Number of shirts =x=10

Q#3

total cost=y=?

for y=10.5x

put x=10

y=10.5*10

cost=y=105

and for other function

for y=7.5x+30

put x=10

y=7.5(10)+30

y=75+30=105

8 0

3 years ago

Read 2 more answers

Out of 8 boys and 6 girls in a high school, a team of seven students is selected. What is the probability that three boys and fo

maria [59]

The probabitily is if they get selected as a team of 7 aswell if they're playing a game of some sort.

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3 years ago

I need help with elimnation

Ivahew [28]

Answer:

what do u mean by that? like what do you want to delete?

3 0

3 years ago