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Delvig [45]
3 years ago
9

Lana wants to graph the height of an amusement park ride as it travels along the track.

Mathematics
2 answers:
likoan [24]3 years ago
6 0
Ok I got this it is A
dalvyx [7]3 years ago
3 0
I can’t do this for you, you have to drag the segments into the boxes. The fifth over is A. then you do the first line segment. Then the third. for D you do the fifth over
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Given the graph below and the equation y = 4x, determine which function has the greatest rate of growth?
Marizza181 [45]

Answer:

Step-by-step explanation:

A slope of 4 has a greater rate of growth than a graph with a slope of 1

4 0
2 years ago
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6 0
3 years ago
Simply 3 small 2+8x4 need answer
evablogger [386]

Answer:

2+32

34

Step-by-step explanation:

First we should multiply before adding after multiplying 8×4 is 32 and add 32+2 then it is 34

7 0
2 years ago
Read 2 more answers
X - 3/2 = 3. Please show your work. Will mark BRAINLIEST
BARSIC [14]

\huge\text{Hey there!}

\mathsf{x-\dfrac{3}{2}=3}

\large\textsf{You have to SIMPLIFY the SIDES of   The  given EQUATION}

\mathsf{x + (-\dfrac{3}{2}) = 3}

\large\textsf{ADD by } \mathsf{\dfrac{3}{2}}\large\textsf{ to BOTH  of the SIDES}

\mathsf{x + (-\dfrac{3}{2})+ \dfrac{3}2{}=3+\dfrac{3}{2}}

\large\textsf{CANCEL out: } \mathsf{-\dfrac{3}{2}+\dfrac{3}{2}}\large\textsf{ because that gives you 0}  

\large\textsf{Keep: } \mathsf{3+ \dfrac{3}{2}}\large\textsf{ because that helps solve for your x-value }

\large\textsf{New equation: }\mathsf{x = 3 + \dfrac{3}{2}}

\mathsf{3+\dfrac{3}{2}}

\large\textsf{SOLVE above and you have your ANSWER}

\mathsf{3+\dfrac{3}{2}=\bf \dfrac{9}{2}}

\boxed{\boxed{\large\textsf{Therefore, your answer is: }\mathsf{\bf x = \dfrac{9}{2}}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

4 0
2 years ago
HELP GEOMETRY find x
morpeh [17]
The Power of a Point theorem tells us, if we draw a line from a certain point, no matter which line we choose, the product of the two distances from the point to the line's intersections with the circles will be constant (or, if the line is tangent to the circle, the value will be equal to the square of the distance to the point of tangency).  So,applying the tangent rule to the x-distance intersection and the two-intersection rule to the other, we have x^2 = 2(2+6) = 16, so taking the square root of the equation gives x=4.
5 0
3 years ago
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