Question

Consider the following quadratic equation. -4x^2+bx-11=0 Determine a possible value of b so that the quadratic has two complex solutions.

Answer 1

Answer:

Step-by-step explanation:

hello,

for $ax^2+bx+c=0$

$\Delta = b^2-4ac$

so here

$\Delta = b^2-4*(-4)*(-11)=b^2-176$

to have two complex solutions we need $\Delta < 0$

so $b^2$

$b < \sqrt{176}=13.266...$

for instance we can take b = 0

hope this helps