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Finger [1]
3 years ago
7

Two beakers plus their contents have a mass of 180.4 grams. The total mass of the contents is 56.8 grams. Write and solve an equ

ation to find the mass of one beaker.
Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer: 2b + 56.8 = 180.4

How I Got The Answer: To represent the number of the mass of a beaker, use the number <em>b</em>. Since the problem says, <em>"Two beakers </em><u><em>plus</em></u><em> their contents have a mass of 180.4 (the contents being 56.8)," </em>create the equation 2b + 56.8 = 180.4.

If you need to solve it, subtract 56.8 from both sides, canceling out 56.8 on the left side and turning 180.4 to 123.6. All you need to do now is divide 2 from each side, and you now have b = 61.8.

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Find the value of P(x)=8x2 + 5at x=1​
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i need help with math You reflect triangle PQR, with coordinates P(-4, -4), Q(-1, -3), and R(-3, -1), across the x-axis, across
meriva

Answer:

After these reflections, the coordinates of P' will be P'(4,-4)

Step-by-step explanation:

<u><em>The question is</em></u>

After these reflections, the coordinates of P' will be?

we have

Triangle PQR, with coordinates P(-4, -4), Q(-1, -3), and R(-3, -1)

Part 1) Reflect triangle PQR across the x-axis

we know that

The rule of the reflection of a point across the x-axis is

(x,y) -----> (x,-y)

Applying the rule of the reflection across the x-axis at the coordinates of triangle PQR

P(-4, -4) -----> P'''(-4,4)

Q(-1, -3) -----> Q'''(-1, 3)

R(-3, -1) ----> R'''(-3, 1)

Part 2) Reflect triangle P'''Q'''R''' across the y-axis

we know that

The rule of the reflection of a point across the y-axis is

(x,y) -----> (-x,y)

Applying the rule of the reflection across the y-axis at the coordinates of triangle P'''Q'''R'''

P'''(-4,4) -----> P''(4,4)

Q'''(-1, 3) ---> Q''(1, 3)

R'''(-3, 1) ---> R''(3, 1)

Part 3) Reflect triangle P''Q''R'' across the x-axis again

we know that

The rule of the reflection of a point across the x-axis is

(x,y) -----> (x,-y)

Applying the rule of the reflection across the x-axis at the coordinates of triangle P''Q''R''

P''(4,4) ---->  P'(4,-4)

Q''(1, 3) ----> Q'(1, -3)

R''(3, 1) ----> R'(3, -1)

therefore

After these reflections, the coordinates of P' will be P'(4,-4)

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4 years ago
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