Area of a rectangle=length x width
You have two rectangles:
First rectangle (the biggest):
length=9 yd
width=12 yd-6 yd=6 yd
Area of the biggest rectangle=(9 yd)(6 yd)=54 yd²
Second rectangle (the smallest)
length=6 yd
width=3 yd
Area of the smallest rectangle=(6 yd)(3 yd)=18 yd²
Area of the ballroom=area of the biggest rectangle + area of the smallest rectangle.
area of the ballroom=54 yd² +18 yd²=72 yd²
Answer:
it would be 34
Step-by-step explanation:
87 dollars hope this helps I can’t really show you how to do it though because I think it will over complicate the problem but
Answer:
m∠E=57°
Step-by-step explanation:
∠FDE=∠FED=(4x+1)° (base angles of isos triangle)
2(4x+1)+(5x-4)=180 (angle sum of triangle)
8x+2+5x-4=180
13x-2=180
13x=180+2
=182
x=182÷13
=14
Hence, m∠E = (4x+1)°
= [4(14)+1]°
= (56+1)°
= 57°
If Micael is 2 years older than sam and sam is 15 than than micael is 17
