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2 years ago

275/20 simplified (lmbo it told me to add more characters)

Mathematics

2 answers:

OLga [1]2 years ago

8 0

Answer:

275/20 = 55/4 = 13 3/4 = 13.75

trapecia [35]2 years ago

6 0

Answer:

55/4

Step-by-step explanation:

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Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

$\sum_{n=1}^{inf}\frac{1}{n^p}$

if p>1 then series converges. In oue case we have:

$\sum_{n=1}^{inf}b_n=\frac{1}{n^4}$

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

5 0

3 years ago

Make a histogram, using a bin width of ten, to display the bowling scores for these 31 players: 87, 104, 79, 94, 117, 82, 72, 11

slavikrds [6]

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,

103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +

xlim(c(70, 120)) +

scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

7 0

2 years ago

3.5+2=2x-10help me HELP ME JIGGABOOS

Genrish500 [490]

3.5 + 2 = 2x - 10
5.5 = 2x -10
+10 +10
—————————
15.5 = 2x
—— ——
2 2

7.75 = x

7.75 is the answer

5 0

7 months ago

Timmykat is on the prowl. The kitten crusader has caught 5 bad guys already today and hopes to be able to catch 2.5 criminals ev

tamaranim1 [39]

30 divided by 2.5
so 12 hours until he catches 30 bad guys

5 0

2 years ago

Type a digit that makes this statement true.

Archy [21]

Answer:

So information at the bottom:

since every number in a thousand spot needs to have 3 digest, we need to add a zero onto 29,422,33<u>0</u>. If we didn’t add a zero, then the problem wouldn’t make much since. So if we divide 29,422,330 by 2, our answer would be 14,711,165. A whole bunch of numbers, but nothing that can’t be solved!

<h3>Hope this helps!✌️</h3>

5 0

2 years ago

Read 2 more answers