Answer:
<h2>
7x + 9 + 5x + 3 = 180</h2>
Step-by-step explanation:
its a supplementary angles:
so the equation is add the two equation equals to 180
7x + 9 + 5x + 3 = 180
Answer:
7
Step-by-step explanation:
twice for joey's age so joeys age is 2 double that it will be 4 so 3+4=7
Answer:
2.62
Step-by-step explanation:

First, write the square root as exponent.

Move the denominator to the numerator and negate the exponent.

Use log product property.

Use log exponent property.

Substitute values.

Answer:
m∠KHL = 43°
Step-by-step explanation:
From the picture attached,
m∠KHL ≅ m∠GHL [Given in the picture]
Now substituting the values of the angles,
(3x + 1) = (5x - 27)
1 + 27 = 5x - 3x
28 = 2x
14 = x
m∠KHL = (3x + 1)° = (3 × 14) + 1
= 42 + 1
= 43°
Therefore, measure of ∠KHL = 43°