The temperature dropped meaning it got lower. Subtract the amount of the drop from the starting temperature:
-4 - 10 = -14
The temperature was -14
The required round of £168.51 to the nearest pound is £169.
Given that,
To round £168.51 to the nearest pound.
<h3>What is rounding of values?</h3>
The rounding of values is superseding a number with an inexact value that has a more ephemeral, more uncomplicated, or more direct representation.
Here,
£168.51 is given in the question and asked to round is to the nearest pound, since after the decimal the number 51 is closer to the nearest zero i.e. 100,
Implies,
The nearest pound to the £168.51 is £169
Thus, the required round of £168.51 to the nearest pound is £169.
Learn more about round the decimal here;
brainly.com/question/867784
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Answer:
5√7
Step-by-step explanation:
What we want to do is first just put the 175 in a sqrt like this:
√175
Next we do prime factorisation to try and simplify further.
175
/ \
25 7
/ \
5 5
We can figure out that this out √5^2 times 7
we can cancel the sqrt and the squared and simplify to 5√7
So there is your answer, 5√7.
If you have any questions feel free to ask. Also for the prime factorisation the formatting may be off, sorry for the inconvenience and have a good day!
Answer:
Therefore,
The value of arcsin(0) is 0° or 180° or 360° or 540° or n×180° so on.
Step-by-step explanation:
To Find:
arcsin(0) in degrees =?
Solution:
' arcsin ' a mathematical function that is the inverse of the sine function.
Therefore, arcsin (x) is called the inverse sine function.
It is the angle whose sine is the number x.
So here we require angle in degree for which the Sine is '0'.
It is also written as
We Know that
Therefore,
Also integer multiples of 180° will have
Where n = integer
Therefore for '0' we can have 2×180° , 3×180° , 4×180°....and so on i.e 360° , 540° and so on
Therefore,
The value of arcsin(0) is 0° or 180° or 360° or 540° or n×180° so on.
Answer:
i think the first one?
Step-by-step explanation:
i dont think its the second or fourth, so most likely the first one, a line joining points
