Question

What is the equation of the line that is parallel to the line y = 1/3x + 4 and passes through the point (6, 5)?

Answer 1

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Find Slope
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y = -1/3 x + 4                                      
Slope = -1/3                                       
Slope of the parallel line = -1/3          


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Insert slope into y = mx + c
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y = -1/3 x + c                                  

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Find y-intercept
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y = -1/3 x + c                                   
at point (6, 5)
5 = -1/3 (6) + c                                 
5 = - 2 + c                                         
c = 5 + 2                                         
c = 7

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Insert y-intercept into y = -1/3x + c
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y = -1/3 x + 7 

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Answer: y = -1/3 x + 7 (Answer B)
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