What is the equation of the line that is parallel to the line y = 1/3x + 4 and passes through the point (6, 5)?

1 answer:

6 0

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Find Slope
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y = -1/3 x + 4
Slope = -1/3
Slope of the parallel line = -1/3

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Insert slope into y = mx + c
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y = -1/3 x + c

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Find y-intercept
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y = -1/3 x + c
at point (6, 5)
5 = -1/3 (6) + c
5 = - 2 + c
c = 5 + 2
c = 7

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Insert y-intercept into y = -1/3x + c
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y = -1/3 x + 7

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Answer: y = -1/3 x + 7 (Answer B)
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