Is 4x=2(2x-2) A no solution or one solution or infinite solution

Write a compound inequality that represents the following scenario:

Inessa05 [86]

The compound inequality that represents the two following scenarios are:

65 < f ≤ 4
8 ≤ f ≤ 12

A compound inequality usually puts together two or more simple inequalities statements together.

Following the assumption from the given information that;

a free single scoop cone = f

The age group of individuals designated to receive the free single scoop cones is:

people who are older than 65 i.e. > 65
children that are 4 or under 4 i.e. ≤ 4

Thus, the compound inequality that is appropriate to express both conditions is:

65 < f ≤ 4

On Tuesdays, the least amount of flavors = 8
The addition amount of extra flavors they can add = 4

Now, we can infer that the total amount of flavors = 8 + 4 = 12

Thus, the compound inequality that is appropriate to express both conditions is:

Least amount of flavors ≤ f ≤ total amount of flavors
8 ≤ f ≤ 12

Therefore, we can conclude that the compound inequality that represents the two following scenarios are:

65 < f ≤ 4
8 ≤ f ≤ 12

Learn more about compound inequality here:

brainly.com/question/24540195?referrer=searchResults

6 0

2 years ago

3[–x + (2 x + 1)] = x – 1

photoshop1234 [79]

Answer:

Step-by-step explanation:

$3[-x + (2 x + 1)] = x -1\\\\\mathrm{Expand\:}3\left(-x+\left(2x+1\right)\right):\quad 3x+3\\3x+3=x-1\\$

Collect like terms

$3x -x =-1-3$

Add similar elements

$2x = -4\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\frac{2x}{2}=\frac{-4}{2}\\\\Simplify\\\\x = -2$

3 0

3 years ago

HELP!! PLEASE!!! THANK YOU!!

Blizzard [7]

Answer:

C. 8x - 3y = 5

Step-by-step explanation:

7 - 3(x - y) = 5x + 2

Standard form: Ax + By = C

7 -3x + 3y = 5x + 2

7 -8x + 3y = 2

-8x + 3y = -5

Divide by -1 to each number

8x - 3y = 5

6 0

3 years ago

After once again losing a football game to the college'ss arch rival, the alumni association conducted a survey to see if alumni

antoniya [11.8K]

Answer:

a) The 90% confidence interval would be given (0.561;0.719).

b) $p_v =P(z>2.8)=1-P(z$

c) Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=64 represent were in favor of firing the coach

$\hat p=\frac{64}{100}=0.64$ estimated proportion for were in favor of firing the coach

$p_o=0.5$ is the value that we want to test since the problem says majority

$\alpha$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of Americans for were in favor of firing the coach

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.64 - 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.561$

$0.64 + 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.719$

And the 90% confidence interval would be given (0.561;0.719).

Part b

We need to conduct a hypothesis in order to test the claim that the proportion exceeds 50%(Majority). :

Null Hypothesis: $p \leq 0.5$

Alternative Hypothesis: $p >0.5$

We assume that the proportion follows a normal distribution.

This is a one tail upper test for the proportion of union membership.

The One-Sample Proportion Test is "used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ ".

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =100*0.64=64>10$

$n(1-p_o)=100*(1-0.64)=36>10$

Calculate the statistic

The statistic is calculated with the following formula:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}$

On this case the value of $p_o=0.5$ is the value that we are testing and n = 100.

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=2.8$

The p value for the test would be:

$p_v =P(z>2.8)=1-P(z$

Part c

Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

6 0

3 years ago

Can someone please explain number 5? please help merely if you know how to do this question

statuscvo [17]

Step-by-step explanation:

The function/equation can be rewritten to fit the variables better. C=10t+2. C stands for the total cost, and t stands for the number of tickets. The total cost of tickets is the amount of tickets ($10 each) plus another $2 (probably some kind of fee).

7 0

2 years ago