3 years ago

Math question down below

Mathematics

1 answer:

Nataly_w [17]3 years ago

8 0

The answer would be 2 2/3.

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Help please? I don’t know much about consecutive integers...

Ugo [173]

Consecutive intergers are numbers that follow each other in order.

The correct answer is 26 and 27 because it equals to 53 which is the closest to 52.

7 0

3 years ago

F(x) = 5x2 − 70x + 258. Complete the square.

astraxan [27]

5(x^2 - 14x + 258/5)
= 5((x-7)^2 -49+258/5)
= 5((x-7)^2 + 13/5)
= 5(x-7)^2 + 13
I belive this is how it should be done

7 0

3 years ago

Solve the system by elimination -3x+4y=16 3x+y=4

Illusion [34]

X's cancel 5y = 20 y= 4 X=0

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3 years ago

What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)

cupoosta [38]

Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

= 40 * (-2) ^4

= 40 * (16)

= 640

5 0

3 years ago

An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"

jolli1 [7]

Answer:

B: a = 1, b= 7, c = -2

Step-by-step explanation:

<u>Quadratic Formula</u>

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when}\:ax^2+bx+c=0$

Given:

$x=\dfrac{-7\pm\sqrt{57}}{2}$

Comparing the terms of the given x-value with those of the quadratic formula:

$\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}=\dfrac{-7\pm\sqrt{57}}{2}$

Therefore:

$2a=2 \implies a=1$
$b = 7$
$b^2-4ac=57$

Using the found values of a and b to solve for c:

$\implies b^2-4ac=57$

$\implies (7)^2-4(1)c=57$

$\implies 49-4c=57$

$\implies -4c=57-49$

$\implies -4c=8$

$\implies c=-2$

In summary: a = 1, b = 7, c = -2

$\implies x^2+7x-2=0$

Therefore, <u>option B</u> is the correct solution.

5 0

2 years ago

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