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denis23 [38]
3 years ago
11

Math question down below

Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0
The answer would be 2 2/3.
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Help please? I don’t know much about consecutive integers...
Ugo [173]
Consecutive intergers are numbers that follow each other in order.

The correct answer is 26 and 27 because it equals to 53 which is the closest to 52.
7 0
3 years ago
F(x) = 5x2 − 70x + 258. Complete the square.
astraxan [27]
5(x^2 - 14x + 258/5)
= 5((x-7)^2 -49+258/5)
= 5((x-7)^2 + 13/5)
= 5(x-7)^2 + 13
I belive this is how it should be done
7 0
3 years ago
Solve the system by elimination -3x+4y=16 3x+y=4
Illusion [34]
X's cancel 5y = 20 y= 4 X=0
7 0
3 years ago
What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)​
cupoosta [38]

Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)​

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

  = 40 * (-2) ^4

  = 40 * (16)

  = 640

5 0
3 years ago
An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"
jolli1 [7]

Answer:

B: a = 1, b= 7, c = -2

Step-by-step explanation:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when}\:ax^2+bx+c=0

Given:

x=\dfrac{-7\pm\sqrt{57}}{2}

Comparing the terms of the given x-value with those of the quadratic formula:

\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}=\dfrac{-7\pm\sqrt{57}}{2}

Therefore:

  • 2a=2 \implies a=1
  • b = 7
  • b^2-4ac=57

Using the found values of a and b to solve for c:

\implies b^2-4ac=57

\implies (7)^2-4(1)c=57

\implies 49-4c=57

\implies -4c=57-49

\implies -4c=8

\implies c=-2

In summary:   a = 1,  b = 7,  c = -2

\implies x^2+7x-2=0

Therefore, <u>option B</u> is the correct solution.

5 0
2 years ago
Read 2 more answers
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