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RSB [31]
3 years ago
7

The measure of an angle is 142.5°. What is the measure of its supplementary angle?

Mathematics
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

37.50°

Step-by-step explanation:

The sum of both sides of an angle is 180°.

180° - 142.5° = 37.50°

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At Scobee Middle School, 35% of the seventh graders ride the bus to school. If there are 320 seventh graders, how many 7th grade
anzhelika [568]

Answer: 112 7th graders ride the bus .

Step-by-step explanation:

Given: The proportion of 7th graders ride the bus to school= 35% = 0.35  [to remove % we divide number by 100]

If there are 320 seventh graders, then the number of 7th graders ride the bus = 320 x (proportion of 7th graders ride the bus to school)

0.35 \times 320

= 112

Hence, 112 7th graders ride the bus .

6 0
3 years ago
Write an equation for the line graphed.
Kay [80]

Answer:

the answer is "d" because the x region is negative 2 and the y region is a positive1

6 0
3 years ago
5x - 2 - 9<br> x + y = -3
erik [133]

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3 0
3 years ago
Talia used 1/3 of a piece of wood for the base of her project 1/4 of the piece of wood for the vertical support and the rest for
Veseljchak [2.6K]

Answer:

The fraction of wood used for horizontal support is \frac{5}{12}.

Step-by-step explanation:

Assume that the total piece of wood is of length 1.

It is provided that Talia used \frac{1}{3} of the piece of wood for the base of he project.

She use \frac{1}{4} of the piece of wood for the for the vertical support.

The remaining wood she used for horizontal support.

The amount of wood used for horizontal support can be computed by the subtracting the amount of wood used for base of the project and vertical support form 1.

Compute the amount of wood used for horizontal support as follows:

Horizontal\ support=1-Base\ of\ project-Vertical\ support\\= 1 - \frac{1}{3}-\frac{1}{4}\\  =\frac{12-4-3}{12} \\=\frac{5}{12}

Thus, the fraction of wood used for horizontal support is \frac{5}{12}.

3 0
3 years ago
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
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